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(9/8)^(3x+12)=1
We move all terms to the left:
(9/8)^(3x+12)-(1)=0
Domain of the equation: 8)^(3x+12)!=0We add all the numbers together, and all the variables
x∈R
(+9/8)^(3x+12)-1=0
We multiply all the terms by the denominator
(+9-1*8)^(3x+12)=0
We add all the numbers together, and all the variables
1^(3x+12)=0
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